I have a Top246YN in three terminal modes trying to determine if it works.
My setup:
48v power supply with 300mA capacity
LED and 10k resistor to test drain current.
47uF cap attached to control line and negative side to neutral.
10k and 100k series power supply pot for control.
Everything seems to work perfectly, the led lights up and when I increase the current to the control pin, the led goes out as if the work cycle was reduced. I look at the voltage of the control line and the shunt goes into action and keeps the line at ~5.8V. The problem is that even if I don't give the current of the control line, the thing still works. I even tried to add a tensile strength down. What do you think's going on? The reason why the IC was removed in the first place was that it did not appear to have a stable reversal. Any ideas?
The reason you see a 5.8V on the control pin is that there is an internal shunt regulator in the TOP246YN. As long as you put a voltage higher than 7V or more in the drainage pin, you will get 5.8V on the control pin. Details can be found in the Top with data sheet.
On the right, when the unit starts, the internal power supply loads the RC circuit at 5.8v to start the soft start. However, if no external feedback is applied before the RC circuit reaches 4.8v, an automatic restart will begin. The automatic start must then put the device into low power mode and attempt to restart the device at a frequency eight times higher than the RC time constant. My problem is that by testing the device as described above when no external feedback is applied, the device continues to work. I wonder if this could be caused by damage to the control spindle.
Yes, if there is no external feedback to the control pin, it means that it is an open loop. At 4.8 V, automatic restart is activated, disabling the output MOSFET and putting the control circuit into low-current sleep mode. The high voltage current source lights up and recharges the external capacity. An internal hysteresis undervoltage comparator keeps the VC within a 4.8V to a 5.8V window by turning the high voltage current source on and off.
No comments:
Post a Comment